What is the 5th significant number of 24.98063

Look at the 2nd significant digit that the number has.

In a decimal, the first significant digit is the first non-zero digit. The 2nd significant digit is the digit after the first.

if it is less than 5 then round the number down by removing the rest of the number after the 1st significant digit and filling in with zeros;

if it is 5 or more then round the number up by adding one on to the 1st digit and removing the rest of the number and filling in with zeros.

Step-by-step explanation:

8726 rounds up to 9000, because the 2nd significant digit is a 7.

73.283 rounds down to 70 because the 2nd significant digit is a 3.

152 rounds up to 200 because the 2nd significant digit is a 5.

0.003826 rounds up to 0.004 because the 2nd significant digit is an 8.

0.60828 rounds down to 0.6 because the 2nd significant digit is a 0.

  5.   y=6; de=7; fg=8

  6.   x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

  y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

  y = 6

of course, the total chord length is the sum of the lengths of its segments.

  de = dh +eh = 3+4 = 7

  fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

  x = lk = mk×nk/jk = 6×7/10 = 4.2

  jl = jk +lk = 10 +4.2 = 14.2

  mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.

i get you, what you should do is think of the positive things that would come out of it. it will make yours parents proud and raise your grade. you should always try and if you can't focus tell the teacher.