Work out area of ABCD

Area of ABCD = 45.1 cm²

Step-by-step explanation:

From the figure attached,

Area of ABCD = Area of ΔBCD + Area of ΔABD

Area of ΔABD =

sin(55°) =

sin(55°) =

AB = 10sin(55°)

AB = 8.19 cm

cos(55°) =

              =

AD = 10cos(55°)

AD = 5.74cm

Area of ΔABD =

                        = 23.51 cm²

Area of ΔBCD =

                        =

tan(38°) =

BE =

Similarly, DE =

Since, BE + DE = 10 cm

CE(1.28 + 1.04) = 10

CE(2.32) = 10

CE = 4.31 cm

Area of ΔBCD =

                       = 21.55 cm²

Area of ABCD = Area of ΔBCD + Area of ΔABD

                        = 21.55 + 23.51

                        = 45.06

                        ≈ 45.1 cm²

12.5 feet

step-by-step explanation: