I NEED HELP ASAP The vertices of \triangle JKL△JKL are J\left(-3,-2\right)J(−3,−2), K\left(1,4\right)K(1,4), and L\left(4,2\right)L(4,2). Which coordinate pairs are vertices of D_5\left(\triangle JKL\right)D 5 ​ (△JKL)?

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

7.3

step-by-step explanation:

$450 i think. hope this ☺

the correct answer is c

good luck love