HELP ME PLEASE!!
HELP ME ANSWER A AND B

a) 4c+3b=11.67

   8c+b=12.89

b)One loaf of bread cost $2.09

  One can of soup costs $1.35

Step-by-step explanation:

Let c= can of soups    Let b= loaf of bread

a) To find the equation, you know that Khalil buys four cans of soup and 3 loafs of bread and 4 cans of soup for $11.67 so that means that the first equation will be 4c+3b=11.67. Then, you know that Khalil buys 8 cans of soup and one bread for $12.89. so the next equation will be 8c+b=12.89. This means the system of linear equations will be

4c+3b=11.67

8c+b=12.89

b) Use elimination to solve this. You want to make one variable from each equation the same so multiply 4c+3b=11.67 by 2. This will look like 2(4c+3b=11.67). Then simplify to get 8c+6b=23.34 and 8c+b=12.89. Because 8 and 8 are the same, you have to subtract the equations from each other making 5b=10.45. Simplify that and you get b= 2.09 so the one loaf of bread cost $2.09. Then  plug 2.09 into 8c+b=12.89. It will look like this 8c+2.09=12.89. Simplify that and you get 8c=10.8. Simplify that again and you will get 1.35 so a can of soup will costs $1.35

Therefore

a) 4c+3b=11.67

   8c+b=12.89

b) One loaf of bread cost $2.09

   One can of soup costs $1.35

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