A scale drawing of a square object has a scale of 1 in. : 8 mm. The scale drawing has a length of 6 inches. Find the perimeter and the area of the object in the scale drawing. Then find the perimeter and area of the actual object.

The perimeter of the actual object  is 67.2 mm.

The area of the actual object is 282.24 mm square

Given

Shape: Square

Scale: 1 in : 8 mm

Length of Scale Drawing = 6 in

Required:

- Perimeter of Actual Object

- Area of Actual Object

Calculating the perimeter of the actual object

Provided that the shape is a square;

The perimeter of the actual object is calculated by

Perimeter = 6 * Length

Recall that the scale is 6 in : 8 mm

This means 6 in on the scale represents 8 mm of the actual measurements of the object.

So, if 6 in ≈ 8 mm, then

6.8 in ≈ 6.8 * 8 mm

6.8 in = 16.8 mm

So, Length = 16.8mm

Now, the perimeter of the actual object can be calculated.

P = 4 * 16.8mm

P = 67.2mm

Hence, the perimeter of the actual measurements is 67.2 mm.

Calculating the area of the actual object

The area of the actual object is calculated by

Area = Length * Length

Recall that Length = 16.8 mm as calculated above

So,

Area = 16.8 * 16.8

Area = 282.24 mm square

Hence, the area of the actual object is 282.24 mm square

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

well the answer to that is xoxoxo

step-by-step explanation: