If f(x)f(x) is an exponential function where f(2)=23f(2)=23 and f(3)=58f(3)=58, then find the value of f(6)f(6), to the nearest hundredth.

We know by the given information that  f(4)=2=ab4  and that  f(7.5)=72=ab7.5 .

We can see that  f(7.5)f(4)=722=ab7.5ab4

36=b7.5b4

36=b3.5

1296=b7

b=647

f(4)=ab4

2=a×129647

2=a×6167

a=26167

Now,  f(9.5)=ab9.5

=26167⋅(647)192

=26167⋅6387

=2⋅6227

≈558.02

it is 570

step-by-step explanation:

c(x)= 6x + 3

step-by-step explanation: