Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. x4 + x − 7 = 0, (1, 2) f(x) = x4 + x − 7 is ---Select--- on the closed interval [1, 2], f(1) = , and f(2) = . Since −5 < ? < 11, there is a number c in (1, 2) such that f(c) = ? by the Intermediate Value Theorem. Thus, there is a ---Select--- of the equation x4 + x − 7 = 0 in the interval (1, 2).

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

translate k to n and reflect across the line containing jk.

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.