when 2x^3 + 3x^2+ax+b id divided by x-2 the remainder is 30, and when divided by x-3 the remainder is 83. Find a and b

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

answer:   c ?

step-by-step explanation:

answer: 270

step-by-step explanation:

you have to times 200 by 1.35 to get your answer

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.