1. Find the volume of a cube with a side of 9 cm. 2. Find the perimeter of a rectangle whose length is 4
cm and breadth is 3 cm.
3. Find the area of a square of side 11 m.
4. Find the area of a rectangle that is 14 m long and 5
m wide.
5. Find the perimeter of an equilateral triangle with
side 15 cm.
I'm in tension right now I am studying for exams and I'm tired it would be nice if you help me out!

Step-by-step explanation:

1. Given,

Side of the cube = 9 cm

Therefore, volume of the cube = side × side × side

= 9cm × 9cm × 9cm

2. Given,

Length of the rectangle = 4cm

Breadth of the rectangle = 3cm

Therefore, perimeter of the rectangle = 2(l+b)

= 2(4cm + 3cm) = 2 × 7cm = 14 cm (Ans)

3. Given,

Side of a square = 11 m

Therefore, area of the square = side × side

= 11 m × 11 m

4. Given,

Length of the rectangle = 14 m

Width of the rectangle = 5 m

Therefore, area of the rectangle = l × b

= 14 m × 5 m

5. Given,

Side of the equilateral triangle = 15 cm

Therefore, perimeter of the triangle = 3 × side

= 3 × 15 cm = 45 cm (Ans)

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.