Problem: ​Prove that the quadrilateral defined by the points F(6,4), R(1,3), O(3,2), G(−2,1) is a parallelogram. What Method/Formula(s) did you select?
(Please explain and show full work)

114 cm²

Step-by-step explanation:

Area of shaded region

= area of circle -area of square

\boxed{area \: of \: circle = \pi {r}^{2} }

areaofcircle=πr

2

Given that radius= 10cm, r= 10cm.

\boxed{area \: of \: square = side \: \times side}

areaofsquare=side×side

Let the length of a side of the square be x cm.

Applying Pythagoras Theorem,

10² +10²= x²

100 +100= x²

x²= 200

x = \sqrt{200}x=

200

Area of square

= x²

= 200cm²

Area of shaded region

= 3.14(10²) -200

= 3.14(100) -200

= 314 -200

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

you