In 2003 a gallon of gas cost $1.75. The cost has risen $0.17 each year since then Write an equation to represent the cost of gas (in gallons) as a function of years.
What would the cost of a gallon of gas be in 16 years?

x + m × y

$4.47

Step-by-step explanation:

The equation and computation is shown below:

Let us assume the cost of gallon be x

Increase each year be m

And, the number of years be y

So, the equation is

= x + m × y

The cost of gallon of gas in 16 years is

= $1.75 + $0.17 × 16

= $1.75 + $2.72

= $4.47

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

600,000,000,000, or 6e14

step-by-step explanation: