URGENT will give brilliant mark For the reaction 2Na + Cl2 2NaCl, how many grams of sodium chloride can be produced from 500g of chlorine? ( atomic masses : Na = 23 , Cl = 35.5 g/mol) * 1 point

112 g

319 g

409 g

825 g​

825 g

Step-by-step explanation:

Here's my work:

500g Cl2 l   1mol Cl2  l  2 mol NaCl   l  58.5 g NaCl

                l   71 g Cl2    l  1 mol Cl2      l    1 mol NaCl  

= 823.94  - the rounding can be a little off

The first thing you have to do is convert the 500 g of Cl2 into moles.  So you get the mass of Cl which is 35.5, but Cl is diatomic by itself so you multiply 35.5 x 2 and get 71.   now on the third column you are comparing the mol ratios of the equation.  The equation is 2Na + Cl2 ---> 2NaCl, so you see that there is no coefficient in front of Cl2 so that means there is 1 mol, and then you see that in the product there is a  coefficient of 2 in front of NaCl so that means there is 2 moles.  Then finally you have to convert the moles backs into grams where you just add the masses of Na and Cl .  You multiply across the top  and then divide that number by the bottom row.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.