Ez pts someebody help find the equation axis of symmetry of y=-2(x-3)^2 +4

 Use the vertex form, y=a(x−h)2+k y = a ( x - h ) 2 + k , to determine the values of a a , h h , and k k . a=−2 a = - 2. h=3 h = 3. k=4 k = 4. The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola. For a quadratic function in standard form, y=ax2+bx+c , the axis of symmetry ... Simplify. x=62 =3. Therefore, the axis of symmetry is x=3 .

Step-by-step explanation: How Do You Find the X- and Y-Intercepts of a Line in Slope-Intercept Form? To find the x-intercept of a given linear equation, plug in 0 for 'y' and solve for 'x'. To find the y-intercept, plug 0 in for 'x' and solve for 'y'.  sorry if I did it wrong I suck at math

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