Mathematics, 28.02.2021 21:10 skaterwolf1317
Please help me with this question! I can't seem to get full marks! I'll give out brainiest!
A, B and C are points on the circumference of a circle. XY is a tangent to the circle at the point A.
Angle BAY=72 and angle ABC=54.
Prove that triangle ABC is an isosceles triangle.
You must give a reason for any statement or any calculation you carry out.
This is my working out:
Angle BCA = 72 degrees (Alternate segment theorem)
A tangent meets a radius at 90 degrees.
Angle BCA + angle ABC = 72 + 54= 126 degrees (Angles in a triangle add up to 180 degrees)
Angle BAC = 180 - (72 + 54) = 54 degrees (angles in a triangle add up to 180 degrees)
Since angle BAC = angle BCA so the triangle is isosceles. AC= BC hence BAC = BCA because they are congruent angles which makes triangle ABC an isosceles triangle.
AC= BC because both of these are equal to the radius of the circle.
Angles in a semicircle are 90 degrees.
Answers: 2
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Please help me with this question! I can't seem to get full marks! I'll give out brainiest!
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