f(x) = sqrt(x + 4) e^(x^2/2), [−1, 1]
Mathematics, 28.02.2021 20:10 justaguy15
Consider the following function and closed interval.
f(x) = sqrt(x + 4) e^(x^2/2), [−1, 1]
![Consider the following function and closed interval.
f(x) = sqrt(x + 4) e^(x^2/2), [−1, 1]](/tpl/images/2185/3754/4ca69.jpg)
Answers: 1
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Consider the following function and closed interval.
f(x) = sqrt(x + 4) e^(x^2/2), [−1, 1]
f(x) = sqrt(x + 4) e^(x^2/2), [−1, 1]
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