A study was done to test the notion that people are taller when they first wake up in the morning than in the evening right before they go to bed. To test this theory, the heights of children in a boarding school in India were measured. Values were recorded (in mm) for each child in the morning and again in the evening. The data is recorded in AMPM-Heights. xlsx (Links to an external site.). You want to determine if the children are taller in the morning than in the evening. Define the differences as AM Height minus PM Height. Compute a 95% confidence interval for the true mean difference of heights. Required:
a. You also want to conduct a hypothesis test to determine if heights are taller in the morning than in the evening. Use a level of significance of α= 0.05. Is the alternative hypothesis for this test one-tailed or two-tailed?
b. Give the test statistic for this test. Round your answer to the three decimal places
c. Give the degrees of freedom for this test.
d. What is the P-value for this test?

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

homozygous. one is homozygous, while two is heterozygous.

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)