Can u help me with this

acc to quesperimeter of figure= 3a^2+15a+9

let missing dimension be x

= x+10a-2+a^2-7+5a=3a^2+15a+9

x+15a+a^2-9=3a^2+15a+9

x=2a^2+18

the answer is somewhere there guys it really . there im just not gonna answer

step-by-step explanation:

but i'm guessing ur first option tho

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2