Mathematics, 28.02.2021 14:00 maxi12312345

50 A jet flies due North far a distance of 50 cm and then on a bearing of N TOE for a furter
km. Find the distance and bearing of the jet from its starting point

50

A jet flies due North far a distance of 50 cm and then on a bearing of N TOE for a furter
km.

Answers: 1

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Answer from: kiarasanchez17

90 km, N 46° E

Step-by-step explanation:

A jet flies due North for a distance of 50 km and then on a bearing of N 70° E for a further 60 km. Find the distance and bearing of the jet from its starting point.

Look at the diagram I drew of this scenario. You can see the jet flies North for 50 km, and then turns at a 70° angle to fly another 60 km. We want to find the distance from the starting point, SP, to angle C (labeled).

This will be the jet's distance from its starting point.

In order to find the bearing of the jet from its starting point, we will need to find the angle formed between distances b and c, labeled angle A.

The Law of Cosines will allow us to use two known sides and one known angle to solve for the sides opposite of the known angle.

In this case, the known angle is 110° (angle B) so we will use the Law of Cosines respective to B.

b² = a² + c² - 2ac cosB

Substitute the known values into the equation and solve for b, the distance from the starting point (A) to the endpoint (C).

b² = (60)² + (50)² - 2(60)(50) cos(110°)b² = 6100 -(-2052.12086) b² = 8152.12086b = 90.28909602b ≈ 90 km

The distance of the jet from its starting point is 90 km. Now we can use this b value in order to calculate angle A, the bearing of the jet.

The Law of Cosines with respect to A:

a² = b² + c² - 2bc cosA

Substitute the known values into the equation and solve for A, the bearing from the starting point (clockwise of North).

(60)² = (90.28909602)² + (50)² - 2(90.28909602)(50) cosA 3600 = 8152.12086 - 6528.909602 cosA-4552.12086 = -6528.909602 cosA0.6972252853 = cosA A = cos⁻¹(0.6972252853) A = 45.79519A ≈ 46°

The bearing of the jet from its starting point is N 46° E. This means that it is facing northeast at an angle of 46° clockwise from the North.

50

A jet flies due North far a distance of 50 cm and then on a bearing of N TOE for a furter
km. Fi

Answer from: Quest

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

$\frac{ab}{bc} =\frac{ad}{ab}$

now, we can cross multiply

and we get

$ab\timesab=ad\times bc$

$ab^2=ad\times bc$

so, this could be step to prove it

Seth is using the figure shown below to prove pythagorean theorem using triangle similarity: in the

Answer from: Quest

total of apples - take away four

6-4 = 2

answer is 2 apples

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50 A jet flies due North far a distance of 50 cm and then on a bearing of N TOE for a furter
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