A bag contains 5 red marbles, 7 white marbles, and 7 blue marbles. You draw 4 marbles out at random, without replacement. Round your answers to 4 decimal places as needed. [What is the probability that all the marbles are red?] What is the probability that exactly two of the marbles are red? What is the probability that none of the marbles are red? I figured out the first one, I just cant figure out the other two.

There are 23 total marbles (9 red, 7 white, and 7 blue).  You want to select 4 marbles randomly without replacement.  We want to know the probability of selecting 4 red marbles.

In this case, we have 3 different colors.  By the formula (1 + 1 + 1)n = 3n, we can see how many possible outcomes of selecting 4 marbles randomly.  Let n = 4.

There are 81 possible outcomes.  We want to see which one has 4 red marbles.  Only 1 possible outcome will give us that.

Therefore, P(4 red marbles) = 1/81 ≈ 0.01235

the reporter's right

step-by-step explanation:

1/4 = .25 / 25%