A quadratic function, f(x) = x2 + bx + 9, is such that there is only one real root. Which of the following are possible values of b? I. b = 2
II. b = 6
III. b = -6
IV. b = -2

A. I, II, III, and IV
B. I and IV only
C. II and III only
D. I only

C

Step-by-step explanation:

Remember that we can use the discriminant to determine the amount of roots that a quadratic function has.

If the determinant equals 0, then we only have one real root.

Our function is given by:

Then the discriminant will be:

We only have one real root, thus our discriminant must be 0:

Solve for b:

Thus:

The answer is both II and III.

The final answer, then is C.

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation: