Out of a deck of 52, what is the probability you draw 4 cards and all four cards are DIAMOND cards? (You can see a deck of cards here.) a
.0026
b
.00000015
c
.077
d
.25

This decimal value is the approximation of the fraction 11/4165

Explanation:

There are 13 diamonds out of 52 total.

The probability of getting a diamond card is 13/52.

After selecting that diamond card and not putting it back, we have 13-1 = 12 diamonds left out of 52-1 = 51 left. The probability of getting another diamond is 12/51.

Then the probability of getting a third diamond is 11/50, and finally 10/49 represents the probability of getting a fourth diamond. Each time we need a new probability, we just subtract 1 from the numerator and denominator.

The numerators are: 13, 12, 11, 10

The denominators are: 52, 51, 50, 49

We'll multiply the four fractions to get our final answer

(13/52)*(12/51)*(11/50)*(10/49) = 0.00264105642257

This rounds to 0.0026 which is roughly a 0.26% chance

The answer as an exact fraction is 11/4165

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.