ABC is a right triangle at A such that

a)

AB = 3(sq rt 48) - 5(sq rt 12) + sq rt3

AB = 3(sq rt 16x3) - 5(sq rt 4x3) + sq rt3

AB = 12(sq rt 3) - 10(sq rt 3) + sq rt3

AB = 3(sq rt 3)

b)

AC = (3 - sq rt 6)(3 + sq rt 6)

AC = 9 + 3(sq rt 6) - 3(sq rt 6) -6

AC = 9 - 6

AC = 3

BC = (3 - sq rt 5)^2 + 2(3sq rt 5-4)

BC = 9 - 6sq rt 5m + 5 + 6sq rt 5 - 8

BC = 9 + 5 - 8 = 6

BC = 6

c)

If right triangle, AB^2 + AC^2 = BC^2

(3sq rt 3)^2 + 3^2 = 6^2

27 + 9 = 36

36 = 36

a .4y4

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step-by-step explanation: