1.y=x+2 2.y=4x-1 its for My math notes and i dont know how to do this!!

x

−

2

=

4

x

+

1

4

x

−

x

=

−

2

−

1

3

x

=

−

3

x

=

−

1

With a value for

x

you can substitute in one of the two equations and obtain

y

. Because both equations has to be valid at the same time, both equations must give you the same number for

y

. Let's try:

y

=

x

−

2

y

=

−

1

−

2

y

=

−

3

and, with the second equation

y

=

4

x

+

1

y

=

4

(

−

1

)

+

1

y

=

−

4

+

1

y

=

−

3

.

It works! Then our solution is given by

x

=

−

1

and

y

=

−

3

.

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation. Point Form: ( 5 2 , 9 2 ) Equation Form: x = 5 2 , y = 9 2

I might be wrong so sorry abt dat

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x