State if the three numbers can be the measures of the sides of a triangle. 6, 9, 10

Need help!

No. They cannot be the measures of the sides of a triangle.

Step-by-step explanation:

Using Pythagorean Theorem (a² + b² = c²) we can find out if these measures match.

The order for a and b doesn't matter, but the measure for c does. c is the hypotenuse, the longest side of a triangle. With these measures, 10 will be the hypotenuse because it is the longest.

6² + 9² = 10²  If this is true, then the measures can be sides of a triangle.

117 = 100   6 squared plus 9 squared equals 117 but 10 squared equals 100. They do not match so the answer is no.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~