An expression to determine the growth rate of a cell is written as 3(1.25)/5. What would be an approximate form of this expression for all values of t? 3(0.25)
O 3(1.05)'
O 3.05
O 3.14

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

a = 11 : 4

b = 38

c = 1 for every 6

step-by-step explanation: