David spots a plane at an angle of elevation of 35 degrees. If he is 2650 feet from the plane, what is the altitude of the plane?

1,519.98 feet

Step-by-step explanation:

Given the following

Angle of elevation = 35 degrees

Distance of david from the plane = 2650feet

Altitude = x

Using SOH CAH TOA

sin theta = opp/hyp

sin 35 = x/2650

x = 2650sin35

x = 2650(0.5736)

x = 1,519.98

Hence the altitude of the plane is 1,519.98 feet

this is false ^.^ lol