What is the point-slope form of a line that has a slope of 3 and passes through point (1, 4)? O y-4-3(x-1)

O 1-y=3(x-4)

OY,-4=3(1-X,)

0 1-Y, = 3(4-x,)​

answer: y = -12x + 108

step-by-step explanation: do (y = m x+b) formula.

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

tangent

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.