Solve the simultaneous equations 3x−2y=27
3x−y=24
x=? y=?
I can do this easily with positives but somehow I just don't understand a bit in negatives, can anyone help?
None of my answers are working.

3x-2y=24 (1)

2x-3y=18 (2)

multiply (1) by 2

6x - 4y = 48

multiply (2) by 3

6x-9y=54

subtracting

6x - 4y = 48

6x - 9y = 54

- + -

5y = -6

y=−

5

−6

3x−2(−

5

6

)=24

=3x+

5

12

=24

=3x=24−

5

12

=

5

120−12

=

5

108

∴x=

5

36

x+y=

5

36−6

=

5

30

=6

x−y=

5

36+6

=

5

42

solution

Step-by-step explanation:

according to me this should be the answer

good luck

hope it becomes helpful to you ☺️☺️

x = 7 and y = -3

Step-by-step explanation:

Subtract equation 1 from 2

3x - 2y = 27

- 3x - y = 24

0 - y = 3

-y = 3

multiply through by minus sign

y = -3

Substitute y = -3 into equation 1

3x - 2(-3) = 27

3x + 6 = 27

collect like terms

3x = 27 - 6

3x = 21

Divide both sides by 3

3x = 21

3 3

x = 7

6hryt%4578855

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)