What is the diameter of a sphere with a volume of 89110 cm”, to the nearest tenth of a centimeter?

Roughly 55.42 cm"

Rounded up is 55.4 cm"

Step-by-step explanation:

Find the radius:

[3*(89110/4pi)]^(1/3)= 27.71

27.71*2= 55.42 cm"

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

read more on -

a

step-by-step explanation: