4. Twice the larger of two numbers is three more than five times the smaller. The sum of four times the larger and three times the smaller is 71. What are the numbers?

Smaller is 5, larger is 14

Step-by-step explanation:

y is larger, x is smaller

2y = 3 + 5x

4y + 3x = 71

Let's solve for y in the first one, then substitute that into the second one.

y = 3/2 + 5/2x

4(3/2 + 5/2x) + 3x = 71

12/2 + 20/2x + 3x = 71

6 + 10x + 3x = 71

13x = 65

x = 5

Substitute that in to the first equation:

2y = 3 + 5(5)

2y = 3 + 25

2y = 28

y = 14

check those answers in the second equation

4y + 3x = 71

4(14) + 3(5)

= 56 + 15 =71

is there a picture

step-by-step explanation:

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.