Mathematics, 25.02.2021 23:20 isaiah1027

I need this asap ty:p Which of the following equations are equations of a direct variation? Choose all that apply.
(a) x=−2y
(b) x+2y=12
(c) 3x−2y=0
(d) 5x^2+y=0
(e) y =0.3x +1.6
(f) y−2=x

Answers: 3

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Answer from: eddrekas8564

(a) x = -2y

Step-by-step explanation:

You can tell if an equation is a direct variation equation if it can be written in the format y = kx.

Note that there is no addition and subtraction in this equation.

Let's put these equations in the form y = kx.

(a) x = -2y

y = x/-2 → y = -1/2x This is equivalent to multiplying x by -1/2, so this is an example of direct variation.

(b) x + 2y = 12

2y = 12 - x y = 6 - 1/2x This is not in the form y = kx since we are adding 6 to -1/2x. Therefore, this is NOT an example of direct variation.

-2y = -3x y = 3/2x This follows the format of y = kx, so it is an example of direct variation.

(d) 5x² + y = 0

y = -5x²This is not in the form of y = kx, so it is NOT an example of direct variation.

(e) y = 0.3x + 1.6

1.6 is being added to 0.3x, so it is NOT an example of direct variation.

(f) y - 2 = x

y = x + 2 2 is being added to x, so it is NOT an example of direct variation.

The following equations are examples of direct variation:

x = -2y 3x - 2y = 0

Answer from: Quest

i think c. but don't trust it.

step-by-step explanation:

Answer from: Quest

$a_1 = 1$ , and

$a_{n+1} = a_n + (n + 1)$ for $n \ge 1$

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote $a_1 = 1$ , $a_2 = 3$ , $a_3 = 6$ , so that we can call

1 the 1st term, 3 the 2nd term, 6 the 3rd term,etc.

note the following:

from the 1st term (1) to the 2nd term (3), we go up by 2,from the 2nd term (3) to the 3rd term (6), we go up by 3from the 3rd term (6) to the 4th term (10), we go up by 4, andfrom the 4th term (10) to the 5th term (15), we go up by 5.

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from $a_1 = 1$ , to get to $a_2 = 3$ , we add $2(=1+1)$

from $a_2 = 3$ , to get to $a_3 = 6$ , we add $3 (=2+1)$

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

$a_1 = 1$ , and $a_{n+1} = a_n +(n + 1)$ for $n \ge 1$

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