Sarah rolled two 6-sided number cubes. Find the probability that the sum of the numbers is equal to 5.

0.2

Step-by-step explanation:

If two number cubes as tossed then the total possible out comes are

Total = {(1,1),(2,1),(3,1),(4,1),(5,1),(6,1),(1,2),(2,2),(3,2),(4,2),(5,2),(6,2),(1,3),(2,3),(3,3),(4,3),(5,3),(6,3),(1,4),(2,4),(3,4),(4,4),(5,4),(6,4),(1,5),(2,5),(3,5),(4,5),(5,5),(6,5),(1,6),(2,6),(3,6),(4,6),(5,6),(6,6)}

Number of elements in sample space are

n(S)=36

Let A and B represent the following events.

A = The sum will be 4.

A = {(1,3),(2,2),(3,1)}

n(A) = 3

B = The sum is less than or equal to 6.

B = {(1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(4,1),(4,2),(5,1)}

n(B)=15

Intersection of both events is

A∩B = {(1,3),(2,2),(3,1)}

n(A∩B) = 3

We need to find the probability that the sum will be 4, given that the sum is less than or equal to 6.

Therefore, the required probability is 0.2.

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12