Christine is selling tickets at a museum. She knows that she has sold at least 40 tickets. The adult tickets cost 14 dollars and the children’s tickets cost 12 dollars. If she knows she has sold no more than $720 worth
of tickets, what are the possible combinations?

Adult tickets cost $80, children ticket cost $40

Step-by-step explanation:

Given data

let the number of adults be x

and the number of children be y

so

x+y= 401

The adult tickets

cost 14 dollars and the children’s tickets cost 12 dollars.

14x+ 12y=  7202

solve 1 and 2

x+y= 40

14x+ 12y=  720

from 1

x= 40-y

put this in 2 in place of x

14(40-y)+12y= 720

560-14y+12y= 720

collect like terms

-2y= 720-560

-2y= 160

y= -160/2

y= -80

put y= 80 in 1

x+80= 40

x= 40-80

x= -40

Hence Adult tickets cost $80, children ticket cost $40

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.