Betty correctly factored 4x^2-6x-4 as (x - 2)(4x + 2). She then claimed that the zeros of that quadratic function f(x) = 4x^2 - 6x – 4 are located x = -2 at x = 1/2 and Did Betty correctly find the zeros of the function?

Determine the domain and range of the given function. the domain is all real numbers all real numbers greater than or equal to –2{x: x = –2, –1, 0, 1, 2}{y: y = –2, –1, 0, 1, 2}. the range is all real numbers all real numbers greater than or equal to –2{x: x = –2, –1, 0, 1, 2}{y: y = –2, –1, 0, 1, 2}.