Marshall spins a prize wheel with 4 segments of equal size, one of which is labeled “winner.” Let X = the number of spins until Marshall wins a prize.

What is the probability that Marshall wins a prize on his 2nd spin?

Recall: P(X = k) = (1 – p)k–1p

Round to 4 decimal places.

 0.1875

EDG 100%

Step-by-step explanation:

answer: options?

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐