Mathematics, 24.02.2021 20:20 leleee10

Please Help 20 POINTS! NEED HELP ASAP! I’ll Thank your Comment if you’re Correct! QUESTION 1
Match each statement with its equivalent statement.
Sin21°
v Sin54°
A. Cos69°
B. Sin47°
C. Sin89°
Sin71°
Sin180
D. Sin68°
Sin33°
E. Cos720
F. Cos360
Cos43°
Cos22°
G. Cos 19°
H. Cos57°
Cos45°
v Cos30°
1. Sin45°
Cos 1°
J. Sin60°

Please Help 20 POINTS! NEED HELP ASAP! I’ll Thank your Comment if you’re Correct!

QUESTION 1
Matc

Answers: 2

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Answers

Answer from: Quest

7. 153.86 ft $^{2}$

8. 12.56 ft $^{2}$

9. 78.5 m $^{2}$

10. 379.94 in $^{2}$

11. 132.665 m $^{2}$

12. 12.56 yd $^{2}$

13. 226.865 ft $^{2}$

14. 113.04 ft $^{2}$

15. 63.585 ft $^{2}$

16. 254.34 m $^{2}$

17. 50.24 cm $^{2}$

step-by-step explanation:

7. $\pi x 7^{2} = \pi * 49 = 153.86 ft^{2}$

8. $\pi * 2^{2} = \pi * 4 = 12.56 ft^{2}$

9. $\pi * 5^{2} = \pi * 25 = 78.5 m^{2}$

10. $\pi * 11^{2} = \pi * 121 = 379.94 in^{2}$

11. $\pi * 6.5^{2} = \pi * 42.25 = 132.665 m^{2}$

12. $\pi * 2^{2} = \pi * 4 = 12.56 yd^{2}$

13. $\pi * 8.5^{2} = \pi * 72.25 = 226.865 ft^{2}$

14. $(\pi /4) * 12^{2} = 0.785 * 144 = 113.04 ft^{2}$

15. $(\pi /4) * 9^{2} = 0.785 * 81 = 63.585 ft^{2}$

16. $(\pi /4) * 18^{2} = 0.785 * 324 = 254.34 m^{2}$

17. $(\pi /4) * 8^{2} = 0.785 * 62 = 50.24 cm^{2}$

Ineed to have answers 6-17 i’m trying to get things done right away so i don’t have to take care of

Answer from: Quest

hey! so 1 (25) out of 4 (100) is 25 so your answer is 25%. it's like quarters!

Answer from: Quest

Answer

1 number

explanation

if we use a graphing calculator, there is only one such number $c\in[0.5,0.75]$ that satisfies the conclusion of the mean value theorem, that is, a number $c\in[0.5,0.75]$ such that

$f'(c) = \dfrac{f(0.75) - f(0.5)}{0.75-0.5},$

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

Answer from: Quest

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range:

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