N a certain​ year, the amount A of garbage in pounds produced after t days by an average household is given by Aequals 7.5t.

The answer is below

Step-by-step explanation:

In a certain​ year, the amount A of garbage in pounds produced after t days by an average household is given by A = 7.5t.

Plot a graph for t > 0

how many days it will take to get 200 pounds of garbage.

Solution:

a) Let the time in days (t) be on the x axis and the amount of garbage (A) in pounds be on the y axis. Therefore:

At t = 0; A = 7.5(0) = 0

At t = 10; A = 7.5(10) = 75

The graph was plotted using the geogebra online graphing tool.

b) number of days require to get 200 pounds of garbage can be gotten by finding the value t for which A = 200. Therefore:

A = 7.5t

t = A / 7.5 = 200 / 7.5

t = 26.67 days

okay wait before i answer, is this for your points on a graph?

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841