A school reserved a banquet hall for the spring dance. In addition to a $100 deposit, each couple must pay $20. If the total cost of the banquet hall is $1, 140. Compare and contrast the steps you used to solve the problem algebraically and arithmetically.

Step-by-step explanation:

1.)20x + 100 = 1440

-Let the number of couples be x. So, the total amount paid by all the couple’s are $20x. School paid $100 as security, so the total amount paid is

$ (20x + 100)

2.) 20x = 1440 - 100 ⇒ 20x = 1040

X = 52

3. ) The security money  is $100, so the couples paid $1440- 100 = $1040 in total. As the couples paid $ 20 each than- = 52

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation:

i think its a and d

step-by-step explanation: