HELP PLEASE ITS JUST ONE QUESTION write an equation of line that passes through point p and is parallel to the line with the given equation

y = 2x - 1

Step-by-step explanation:

The given line is y = 2x - 6.

It is in the y = mx + b form, where m is the slope, so its slope is 2.

We need a line that passes through point P(3, 5) and has slope 2.

y = mx + b

Put the slope in m.

y = 2x + b

Use the given point with x = 3 and y = 5 and solve for b.

5 = 2(3) + b

b + 6 = 5

b = -1

The equation is

y = 2x - 1

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

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