write an equation in slope-intercept form for the line that passes through (-2,5) and is perpendicular to the line described by y=-2x+6

Step-by-step explanation:

The product of slopes of perpendicular lines is -1

y = - 2x + 6  ⇒   m₁ = - 2

m₁m₂ = -1

-2m₂ = -1

m₂ = ⁻¹/₋₂ = ¹/₂

The Point-Slope form of equation of a line with slope of "m" and passing through point (x₁, y₁) is:  y - y₁ = m(x - x₁)

m = ¹/₂

(-2, 5)  ⇒  x₁ = -2,  y₁ = 5

So the equation in point-slope form:

                                                  y - 5 = ¹/₂(x - (-2))

Therefore:

y - 5 = ¹/₂x + 1

y = ¹/₂x + 1 + 5

i dont know

step-by-step explanation:

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse