Use the Distributive Property to write each expression as an equivalent expression. Then evaluate the expression. **SHOW THE PROPERTY** 1. 2 5(s + 20) and 2. –6(12 – 8)

1. 2/5s + 8

2. -24

Step-by-step explanation:

1.

2/5(s + 20)

(2/5)(s) + (2/5)(20)

2/5s + 8

2.

-6(12 - 8)

(-6)(12) - (-6)(-8)

-72 + 48

-24

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation:

b.

step-by-step explanation:

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