Quadrilateral ABCD is rotated 90 degrees about the origin. what are the coordinates of quadrilateral A'B'C'D'? a. A' ( -5, -5), B' (-5, -1), C' (-2, -1), D' (-1,-5)
B. A' (5,-5), B' (5, -1), C' (2, -1) D' (1,-5)
C. A' (5,-5) B' (1, -5) C' (1,-2) D'(5,-1)
D. A' (-5,5) B' (-1, 5) C' (-1.2) D' (-5,1

please i would really love some help i dont understand this lesson but i need to have it done

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation:

i think its a.

hope this