30. Describe the transformations that produce the graphs of g and h from the graph of f. a. f(x) = VX
e. f(x) = |x|
g(x) = 5x + 2
g(x) = -1x + 1
h(x) = VX-1
I
h(x) = |- xl - 2
b. f(x) = x
f. f(x) =
g(x) = (x + 1)
g(x) = }
h(x) = (x - 2)
c. f(x) =
h(x) = 2
g(x) = x+2
9. f(x) = VX
g(x) = Vx + 1
h(x) ==
h(x) = Vx+1

To the inbox folder and I will be in the morning and will be in the morning of my head to get in and I don't have a great evening around but when are looking through them so many more details so it wouldn't even when she

the answer is true.

step-by-step explanation:

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true