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Mathematics, 23.02.2021 08:40 gbrightwell

Use continuity to evaluate the limit. lim
xβ†’9 16+√x/√16+x
Consider the intervals for which the numerator and the denominator are continuous.
The numerator 16+√x
is continuous on the interval Correct The denominator √16+x is continuous and nonzero on the interval

The interval for which the quotient is continuous is the intersection of the above intervals. Therefore, the quotient 16+√x/√16+x is continuous on the interval
Since x=9 is in the interval [0,∞) , then f is continuous at x=9 . Therefore, limxβ†’9
16+√x/√16+x=f(9)=

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Use continuity to evaluate the limit. lim
xβ†’9 16+√x/√16+x
Consider the intervals for...
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