In the given figure, ABCD is a rectangle in which ∠APB = 100°. The value of x is:​

Given that angle APB = 100°

Angle CPB = 180°- 100°. (Angle APB and CPB form a linear pair)

We know all triangles formed here are isosceles

Therefore,

We can take angle PBC= angle PCB = x

Now,

Angle CPB+ x + x = 180°. ( Triangle sum property)

100° + 2x = 180°

2x = 180°- 100°

2x= 80°

x= 80°/2

x= 40°

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