One number is seven more than six times another number. If the sum of the numbers is 21, find the numbers

the two numbers are 2 and 19

Step-by-step explanation:

Let one of the numbers be x

and the second be   7+ 6x

so that the sum of the two numbers which totals 21 be expressed as  

x + (7+ 6x) = 21

x+ 7+6x= 21

7 + 7x = 21

7x= 14

x= 14/7 = 2

one of the numbers = 2

the other number given as

7+ 6x = 7+ 6 x 2= 7+12= 19

The numbers are 2 and 19 .

2 and 19 PLZ GIVE BRAINLIEST

Step-by-step explanation:

just did the question, 21= x + (7 + 6x)

21=7+7x

-7   -7

14=7x

14÷7=7x÷7  

2=x

x=2

now 21-2=19

so answer is 2 and 19

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3