1 and 2 I need this before 10 pm please ASAP I need it quick or I get a bad grade

A. 6 feet

B. 38 feet of fencing total

Step-by-step explanation:

a. We are given 78 square feet as the total area that the fence encloses. Given this, we can use the A=l*w to solve for the side lengths.

A=l*w

Plug in known variables and simplify...

Step 1: Subtract 78 from both sides.

x^2+7x−78=78−78

x^2+7x−78=0

Step 2: Factor left side of equation.

(x−6)(x+13)=0

Step 3: Set factors equal to 0.

x−6=0 or x+13=0

x=6 or x=−13

For this case we will need to use the positive value.

so to check the answer, we can plug in 6 for x and check if it will equal 78.

(6+7)(6)

13*6

78

b. now given the value of x, we need to solve for the total amount of fencing by finding the perimeter.

We already know that one side is 6+7 or 13, and the other side is 6, so to find perimeter we use the formula 2l+2w

and solve...

2*13+2*6

26+12

38

35 is an outlier

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb