How does the graph of g(x)=1/x-5. +2 compare to the graph of the parent function f(x)=1/x

x value of vertical asymptote and y value of horizontal asymptote

Step-by-step explanation:

The graph of 1/x approaches infinity as x approaches 0 (the vertical asymptote)

As x gets either bigger or smaller, 1/x approaches the x-axis (from above on the positive side, from below on the negative side) (the horizontal asymptote)

Consider 1/(x-5) + 2, at what value of x does the graph 'go nuts' ?

When the bottom of the fraction becomes 0, x - 5 becomes 0 when x = 5, so the vertical asymptote of g(x) is at x=5

What value of y does f(x) approach as x gets more positive or more negative - as x gets bigger (as an example), y approaches 0

What y value does g(x) approach as x gets bigger?  Well, as x gets big, 1/(x-5) gets small, approaching 0.  The smallest 0 + 2 can get is 2, so y=2 is the horizontal asymptote