A plane leaves an airport traveling at 400 mph in the direction N 45° E. A wind is blowing at 40 mph in the direction N 45° W. What is the ground speed of the plane? 400 mph
402 mph
429 mph
440 mph

402 mph

Step-by-step explanation:

Draw a right triangle with 400 and 40 as the two legs.

You know this is a right angle because 45 degrees NE is perpendicular to 45 degrees NW. (imagine a compass)

So, the two side lengths are 400 and 40

Using the Pythagorean theorem, (a^2 + b^2 = c^2) you can see that the answer is 401.995, or 402

B

Step-by-step explanation:

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

false

step-by-step explanation:

the reason i say this is because for a certain length of sides you can pick any two and the length is wither equal or greater than the third side and in this case it's not.

3 + 5 = 8

8 is smaller than 9 which is the third side.

hope this : )