In the paper airplane shown abcd is congruent to efgh angle b= angle bcd= 90 and angle bad = 143 find angle feh

Angle FEH = 143.

Step-by-step explanation:

Given : in the paper airplane shown ABCD is congruent to EFGH ... angle B= angle BCD= 90 and angle BAD = 143.

To find : angle FEH.

Solution : We have given quadrilateral ABCD is congruent to EFGH.

Shapes of quadrilateral ABCD and  EFGH is trapezoid.

By congruent rule : side AB ≅ EF, BC≅FG, CD≅GH, DA≅HE and all corresponding angles are equal.

By given statement angle B = angle BCD = 90 and angle BAD = 143

We can see by congruent rule angle BAD ≅ angle FEH = 143.

Therefore, angle FEH = 143.

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.